Bitcoin probably won't drop to $1. If Bitcoin falls from $63,000 to $1, assuming a daily compound decline of 5% (meaning 95% of its value remains each day), this is a standard exponential decay problem.

Calculation formula:
Final value = Initial value × 0.95^n
1 = 63000 × 0.95^n
n = log(1 / 63000) / log(0.95) ≈ 215.445 days
Since the number of days must be an integer and we're interested in when it drops to or below $1:
• After day 215: value ≈ $1.023 (still slightly above $1)
• After day 216: value ≈ $0.972 (already below $1)
So, strictly speaking, it takes 216 days for the price to fall below $1.
Exact answer:
216 days (by the end of day 216, the price has dropped to about $0.97).
How to quickly verify this yourself (using a calculator or phone):
1. Enter 63000
2. Multiply by 0.95 repeatedly, approximately until the 215th time, leaving about 1.02
3. Multiply once more (the 216th time), and it drops to 0.97
This means that even with a steady 5% daily decline, Bitcoin from $63,000 to near zero (or close to $1) takes a little over half a year — much slower than many people imagine the "crash" to be, but still quite dramatic. 😂